CS/IT Gate Yearwise
CS/IT Gate 2025 (Set 2)
CS/IT Gate 2024 (Set 1)
CS/IT Gate 2024 (Set 2)
CS/IT Gate 2023
CS/IT Gate 2022
CS/IT Gate 2021 (Set 1)
CS/IT Gate 2021 (Set 2)
CS/IT Gate 2020
CS/IT Gate 2019
CS/IT Gate 2018
CS/IT Gate 2017 (Set 1)
CS/IT Gate 2017 (Set 2)
CS/IT Gate 2016 (Set 1)
CS/IT Gate 2016 (Set 2)
CS/IT Gate 2015 (Set 1)
CS/IT Gate 2015 (Set 2)
CS/IT Gate 2015 (Set 3)
CS/IT Gate 2014 (Set 1)
CS/IT Gate 2014 (Set 2)
CS/IT Gate 2014 (Set 3)
CS and IT Gate 2017 Set-2 Questions with Answer
Ques 1 Gate 2017 Set-2
In a file allocation system, which of the following allocation scheme(s) can be used if no external fragmentation is allowed?
I. Contiguous
II. Linked
III. Indexed
Ques 2 Gate 2017 Set-2
Let p, q, r denote the statement "It is raining", "It is cold", and "It is pleasant", respectively. Then the statement "It is not raining and it is pleasant, and it is not pleasant only if it is raining and it is cold" is represented by:
Ques 3 Gate 2017 Set-2
"We lived in culture and denied any merit to literally works, Considering them important only when they were handmaidens to something seemingly more urgent - namely ideology. This was a country where all gestures even the most private , interpreted as political terms." The author^^s believes that ideology is not as important as literature is revealed by the word
Ques 4 Gate 2017 Set-2
X is 30 digit number starting with 4 followed 7. Then number X3 will have
The number of digits in a number. If a number N has d digits, then:
10d-1 ≤ N < 10d
For finding digits in X3, I can use logarithms. The number of digits in X3 is:
Number of digits = floor(log10(X3)) + 1
Number of digits = floor(3 × log10(X)) + 1
Since X is a 30-digit number starting with 47, I can estimate its range:
• Minimum value: X ≥ 47 × 1028 (smallest 30-digit number starting with 47)
• Maximum value: X < 48 × 1028 (before it becomes 48...)
The minimum case:
X = 47 × 1028
log10(X) = log10(47) + 28
log10(47) ≈ 1.672 (since log10(47) is between log10(10) = 1 and log10(100) = 2)
So, log10(X) ≈ 1.672 + 28 = 29.672
Therefore:
Number of digits in X3 = floor(3 × 29.672) + 1
= floor(89.016) + 1
= 89 + 1
= 90
Verifying with the maximum case:
X < 48 × 1028
log10(48) ≈ 1.681
log10(X) < 1.681 + 28 = 29.681
Number of digits = floor(3 × 29.681) + 1 = floor(89.043) + 1 = 89 + 1 = 90
Both cases give me 90 digits.
Ques 5 Gate 2017 Set-2
There are three boxes, one contains apples, another contains oranges and last one contains both apples and oranges. All three are known to be incorrectly labelled. You are permitted to open just one box and then pull out and inspect only one fruit. Which box would you open to determine the contents of all three boxes?
Ques 6 Gate 2017 Set-2
The numbers of the roots of ex + 0.5x2 -2 = 0 in the range [-5, 5] are
Ques 7 Gate 2017 Set-2
Choose the option with words that are not synonyms.
Ques 8 Gate 2017 Set-2
There are 3 red socks, 5 green socks and 3 blue socks. You choose 2 socks. The probability that they are of the same color is
Ques 9 Gate 2017 Set-2
Saturn is __________ to be seen on a clear night with the naked eye?
Ques 10 Gate 2017 Set-2
There are 5 buildings called V, W, X, Y, Z in a row (not necessarily in order). V is to the West of W, Z is to the East of X and the West of V. W is to West of Y. Which building is in the middle?
Ques 11 Gate 2017 Set-2
A test has questions worth 100 marks totals. There are two types of questions, multiple choice questions are worth 3 marks each and essay questions are worth 11 marks each. How many multiple choice questions does the exam have?
Ques 12 Gate 2017 Set-2
The minimum possible number of states of a deterministic finite automaton that accepts a regular language L = {w1aw2 | w1, w2 ∈{a,b}* , |w1| = 2, w2>=3} is_______
Ques 13 Gate 2017 Set-2
Identity the language generated by following grammar where S is the start variable.
X --> aX | a
Y --> aYb | ∈
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