Textile Engineering > GATE 2026 > Polymer Chemistry - PET Synthesis
High molecular weight PET is synthesised by maintaining two monomers in 1:1 molar ratio. If the mass of terephthalic acid (C8H6O4) is taken as 100 g, then the mass of ethylene glycol (C2H6O2) needed would be _______________ g. (rounded off to two decimal places)

Correct : 37.36

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PET synthesis high molecular weight PET molar ratio terephthalic acid ethylene glycol textile engineering gate GATE 2026 polymer synthesis mass ratio PET polymer chemistry

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