Solve y√(1-x²)dy+x√(1-y²)dx=0 | GATE 2020 Mining Engineering

Mining Engineering > GATE 2020 > Calculus

For the differential equation y√(1-x²)dy+x√(1-y²)dx=0, assuming the constant of integration to be C, the general solution is

1/(√1-x²)+1/(√1-y²)=C

y(√1-x²)+x(√1-y²)=C

√(1-x)+√(1-y)=C

√(1-x²)+√(1-y²)=C

Correct : d

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