Mining Engineering > GATE 2020 > Calculus
For the differential equation y√(1-x2)dy+x√(1-y2)dx=0, assuming the constant of integration to be C, the general solution is
A
1/(√1-x2)+1/(√1-y2)=C
B
y(√1-x2)+x(√1-y2)=C
C
√(1-x)+√(1-y)=C
D
√(1-x2)+√(1-y2)=C

Explanation

Correct : d

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