Metallurgical Engineering > GATE 2026 > Ellingham Diagram
With reference to the Ellingham diagram, the standard Gibbs free energy change for the oxidation of solid metal M (s) and liquid metal M (l) is given below:
Reaction I: M (s) + O2 (g) → MO2 (s)
ΔG° = (− 338900 − 15.2T lnT + 247T) Joules; from T = 300 K to melting point.
Reaction II: M (l) + O2 (g) → MO2 (s)
ΔG° = (− 390800 − 15.2T lnT + 285.3T) Joules; from melting point to T = 1800 K
The melting point of the metal M (rounded off to one decimal place) is _______________ Kelvin.
Reaction I: M (s) + O2 (g) → MO2 (s)
ΔG° = (− 338900 − 15.2T lnT + 247T) Joules; from T = 300 K to melting point.
Reaction II: M (l) + O2 (g) → MO2 (s)
ΔG° = (− 390800 − 15.2T lnT + 285.3T) Joules; from melting point to T = 1800 K
The melting point of the metal M (rounded off to one decimal place) is _______________ Kelvin.
Correct : 1355.1
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