Electrical Engineering > GATE 2026 > Protection - Current Transformers
In the circuit shown, the phase currents are IA = 572.812 + j50.115 A, IB = −254.525 − j459.175 A, IC = −207.083 + j444.091 A.
Given that the CTs are ideal with no saturation, and the turns ratio of the Main CT is 300:5 and that of the Auxiliary Transformer (YnΔ) is 2:1 on every phase, the value of IAR, rounded off to three decimal places, is:
A
0 A
B
0.653 ∠17.556° A
C
537.240 ∠4.105° A
D
8.954 ∠4.105° A

Correct : d

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