Electrical Engineering > GATE 2025 > Probability
Consider discrete random variables X and Y with probabilities as follows:
P(X=0 and Y=0)=1/4
P(X=1 and Y=0)=1/8
P(X=0 and Y=1)=1/2
P(X=1 and Y=1)=1/8
Given X=1, the expected value of Y is
P(X=0 and Y=0)=1/4
P(X=1 and Y=0)=1/8
P(X=0 and Y=1)=1/2
P(X=1 and Y=1)=1/8
Given X=1, the expected value of Y is
Correct : b
Similar Questions
Let X be a discrete random variable that is uniformly distributed over the set {-10,-9,...,0,...,9,10}. Which of the following random variables is/are uniformly...
Given a fair six-faced dice where the faces are labelled '1', '2', '3', '4', '5', and '6', what is the probability of getting a '1' on the first roll of the dic...
The expected number of trials for the first occurrence of a "head" in a biased coin is known to be 4. The probability of the first occurrence of a "head" in the...
Total Unique Visitors
Loading......