Electrical Engineering > GATE 2021 > Capacitance
Consider a large parallel plate capacitor. The gap d between the two plates is filled entirely with a dielectric slab of relative permittivity 5. The plates are initially charged to a potential difference of V volts and then disconnected from the source. If the dielectric slab is pulled out completely, then the ratio of the new electric field E\_{2} in the gap to the original electric field E\_{1} is
Correct : 5
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