EC > GATE 2025 > Sampling
Consider a continuous-time finite-energy signal f(t) whose Fourier transform vanishes outside the frequency interval [-ωcc], where ωc is in rad/sec.
The signal f(t) is uniformly sampled to obtain y(t)=f(t)p(t). Here, p(t)=Σn=-∞δ(t-τ-nTs), with δ(t) being the Dirac impulse, Ts>0, and τ>0. The sampled signal y(t) is passed through an ideal lowpass filter h(t)=ωcTssin(ωct)/(πωct) with cutoff frequency ωc and passband gain Ts.
The output of the filter is given by
A
f(t) if Ts<π/ωc
B
f(t-τ) if Ts<π/ωc
C
f(t-τ) if Ts<2π/ωc
D
Tsf(t) if Ts<2π/ωc

Correct : c

Similar Questions

Consider a continuous-time signal defined as x(t) = [sin(&pi; t/2)/(&pi; t/2)] * &sum;n=-&infin;&infin; &delta;(t-10n) where '*' denotes the convolution operati...
#902 Fill in the Blanks
Consider two real valued signals, x(t) band-limited to [-500 Hz, 500 Hz] and y(t) band-limited to [-1 kHz, 1 kHz]. For z(t) = x(t) · y(t), the Nyquist sampling...
#940 Fill in the Blanks
Let x(t) = cos(10πt) + cos(30πt) be sampled at 20 Hz and reconstructed using an ideal low-pass filter with cut-off frequency of 20 Hz. The frequency/frequencies...
#1070 MCQ

Related Topics

continuous time signal finite energy signal Fourier transform uniform sampling Dirac delta function lowpass filter ideal lowpass filter signal processing gate EC GATE 2025 signal reconstruction time delay frequency cutoff filter signal recovery EC

Unique Visitor Count

Total Unique Visitors

Loading......