EC > GATE 2024 > Calculus
For a real number $x>1$,
$\frac{1}{log_{2}x}+\frac{1}{log_{3}x}+\frac{1}{log_{4}x}=1$
$\frac{1}{log_{2}x}+\frac{1}{log_{3}x}+\frac{1}{log_{4}x}=1$
Explanation
Correct : C
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