EC > GATE 2024 > Amplitude Modulation
An amplitude modulator has output (in Volts)
s(t) = A cos(400πt) + B cos(360πt) + B cos(440πt).
The carrier power normalized to 1Ω resistance is 50 Watts.
The ratio of the total sideband power to the total power is 1/9.
The value of B (in Volts, rounded off to two decimal places) is

Correct : 1

Similar Questions

Consider the following amplitude modulated signal: s(t)=cos(2000πt)+4cos(2400πt)+cos(2800πt). The ratio (accurate to three decimal places) of the...
#429 Fill in the Blanks
Let c(t)=Accos(2πfct) and m(t)=cos(2πfmt) It is given that fc>>5fm. The signal c(t)+m(t) is applied to the input of a non-linear device, whose output...
#441 MCQ
The unmodulated carrier power in an AM transmitter is 5 kW. This carrier is modulated by a sinusoidal modulating signal. The maximum percentage of modulation is...
#584 Fill in the Blanks

Related Topics

amplitude modulation EC GATE 2024 carrier power normalization sideband power ratio EC gate questions modulation theory sideband power calculation GATE EC 2024 sideband power to total power ratio

Unique Visitor Count

Total Unique Visitors

Loading......