EC > GATE 2023 > Block Diagram Reduction
In the following block diagram, R(s) and D(s) are two inputs. The output Y(s) is expressed as Y(s) = G1(s)R(s) + G2(s)D(s). G1(s) and G2(s) are given by
A
G1(s) = G(s)/1 + G(s) + G(s)H(s) and G2(s) = G(s)/1 + G(s) + G(s)H(s)
B
G1(s) = G(s)/1 + G(s) + H(s) and G2(s) = G(s)/1 + G(s) + H(s)
C
G1(s) = G(s)/1 + G(s) + H(s) and G2(s) = G(s)/1 + G(s) + G(s)H(s)
D
G1(s) = G(s)/1 + G(s) + G(s)H(s) and G2(s) = G(s)/1 + G(s) + H(s)

Correct : a

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