EC > GATE 2020 > BJT
The base of an npn BJT T1 has a linear doping profile NB(x) as shown below. The base of another npn BJT T2 has a uniform doping NB of 10¹⁷ cm⁻³. All other parameters are identical for both the devices. Assuming that the hole density profile is the same as that of doping, the common-emitter current gain of T2 is
A
approximately 2.0 times that of T1.
B
approximately 0.3 times that of T1.
C
approximately 2.5 times that of T1.
D
approximately 0.7 times that of T1.

Correct : mta

Similar Questions

Which of the following statements is/are true for a BJT with respect to its DC current gain (β)?
#73 MSQ
The correct circuit representation of the structure shown in the figure is
#358 MCQ
A BJT is biased in forward active mode. Assume VBE = 0.7 V, kT/q = 25 mV and reverse saturation current IS = 10-13 A. The transconductance of the BJT (in mA/V)...
#956 Fill in the Blanks

Related Topics

BJT current gain npn BJT T1 npn BJT T2 uniform doping linear doping profile hole density profile GATE EC 2020 BJT current gain comparison BJT doping profile GATE electronics BJT current gain calculation

Unique Visitor Count

Total Unique Visitors

Loading......