EC > GATE 2017 SET-1 > Probability
Three fair cubical dice are thrown simultaneously. The probability that all three dice have the same number of dots on the faces showing up is (up to third decimal place)

Correct : 0.0277

When three fair dice are thrown simultaneously, we need to find the probability that all three show the same number.

A fair die has 6 possible outcomes (1, 2, 3, 4, 5, 6).
When three dice are thrown together, the total number of possible outcomes is:
6 ร— 6 ร— 6 = 216

Now let me count the favorable outcomes where all three dice show the same number:
(1, 1, 1) - all three show 1
(2, 2, 2) - all three show 2
(3, 3, 3) - all three show 3
(4, 4, 4) - all three show 4
(5, 5, 5) - all three show 5
(6, 6, 6) - all three show 6

So there are 6 favorable outcomes.

The probability is calculated as:
Probability = Number of favorable outcomes / Total number of outcomes
Probability = 6/216
Probability = 1/36
Probability = 0.027777...

Rounding to three decimal places:
Answer: 0.028 (or 0.027)

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