EC > GATE 2014 SET-4 > BJT
Consider two BJTs biased at the same collector current with area A1 = 0.2 μm × 0.2 μm and A2 = 300 μm × 300 μm. Assuming that all other device parameters are identical, kT/q = 26 mV, the intrinsic carrier concentration is 1 × 1010 cm−3, and q = 1.6 × 10−19 C, the difference between the base-emitter voltages (in mV) of the two BJTs (i.e., VBE1 – VBE2) is _____.
Correct : 380
Similar Questions
Which of the following statements is/are true for a BJT with respect to its DC current gain (β)?
The base of an npn BJT T1 has a linear doping profile NB(x) as shown below. The base of another npn BJT T2 has a uniform doping NB of 10¹⁷ cm⁻³. All other param...
The correct circuit representation of the structure shown in the figure is
Total Unique Visitors
Loading......