Computer Sciences > GATE 2026 SET-2 > Computer Networks
Consider a file of size 4 million bytes being transferred between two hosts connected via a path consisting of three consecutive links of bandwidth 2 Mbps, 500 kbps, and 1 Mbps, respectively. ... Which one of the following is the total time (in seconds) to transfer the file?
A
731
B
64
C
8
D
16

Correct : b

To find the total time to transfer the file, we must determine the total file size in bits and identify the slowest link in the network path, known as the bottleneck bandwidth.

Calculating the Total File Size
The file size is given as 4 million bytes. Since network transmission speeds are measured in bits per second, we first need to convert bytes to bits (1 byte = 8 bits).
File Size = 4 × 106 bytes = 4 × 106 × 8 bits = 32 × 106 bits.

Identifying the Bottleneck Bandwidth
The network path consists of three consecutive links:
Link 1: 2 Mbps = 2 × 106 bps
Link 2: 500 kbps = 500 × 103 bps = 0.5 × 106 bps
Link 3: 1 Mbps = 1 × 106 bps
In a multi-link network, the overall data transfer rate is always constrained by the slowest link. Comparing the three, the minimum bandwidth is 500 kbps (0.5 × 106 bps).

Calculating the Transfer Time
Because network data is pipelined (sent as a continuous stream of packets) and processing/propagation delays are negligible, the total transfer time is simply the time it takes to push the entire file through that bottleneck link.
Total Time = File Size / Bottleneck Bandwidth
Total Time = (32 × 106 bits) / (0.5 × 106 bps)
Total Time = 32 / 0.5 = 64 seconds.

Correct Answer: B (64) βœ“

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bottleneck bandwidth GATE 2026 GATE CS 2026 Set-2 Q21 network link transfer time file transfer time computer networks bottleneck link bandwidth 4 million bytes 500 kbps transfer time computer networks GATE previous year questions

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