Computer Sciences > GATE 2026 SET-2 > Quantitative Aptitude
A day can only be cloudy or sunny. The probability of a day being cloudy is 0.5, independent of the condition on other days. What is the probability that in any given four days, there will be three cloudy days and one sunny day?
A
1/4
B
3/4
C
2/3
D
3/8

Correct : a

The correct answer is Option A — 1/4.
This is a classic Binomial probability problem. Each day independently has probability p = 0.5 of being cloudy and q = 0.5 of being sunny. We need exactly 3 cloudy days out of 4, which follows the binomial formula:
P(X = k) = C(n, k) × pk × q(n−k)
Here n = 4, k = 3, p = 0.5, q = 0.5:
P(X = 3) = C(4, 3) × (0.5)3 × (0.5)1 = 4 × (1/8) × (1/2) = 4/16 = 1/4.
C(4, 3) = 4 accounts for the 4 different ways to choose which 3 of the 4 days are cloudy (CCCS, CCSC, CSCC, SCCC). Each such arrangement has probability (0.5)3 × (0.5)1 = 1/16. Multiplying gives 4/16 = 1/4.
Why not Option D (3/8)? A common mistake is computing C(4,3) × (0.5)³ = 4/8 = 3/8, forgetting to multiply by (0.5)¹ for the one sunny day. Since the sunny day also has probability 0.5, it must be included in the product — giving (0.5)⁴ total, not (0.5)³.
Why not Option A being confused with 1/4 by intuition? One might guess 1/4 simply because 1 out of 4 days is sunny, but the actual derivation confirms the answer rigorously through the binomial formula.

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