Computer Sciences > GATE 2026 SET-1 > Probability
Let X be a random variable which takes values in the set {1, 2, 3, 4, 5, 6, 7, 8}.
Further, Pr(X = 1) = Pr(X = 2) = Pr(X = 5) = Pr(X = 7) = 1/6 and
Pr(X = 3) = Pr(X = 4) = Pr(X = 6) = Pr(X = 8) = 1/12.

The expected value of X, denoted by E[X], is equal to ___________. (rounded off to two decimal places)

Correct : 4.25

To find the expected value of a discrete random variable X, we use the standard formula for expected value (which is also the mean of the distribution):
E[X] = ∑ [x × P(X = x)]
This means we must multiply each possible value of X by its corresponding probability, and then add all those products together.
1. Group the values by their probabilities
We are given two different probability values in this problem:
- Values with probability 1/6: {1, 2, 5, 7}
- Values with probability 1/12: {3, 4, 6, 8}
2. Calculate the sum for the first group (Probability = 1/6)
Sum1 = 1(1/6) + 2(1/6) + 5(1/6) + 7(1/6)
Sum1 = (1 + 2 + 5 + 7) / 6
Sum1 = 15 / 6 = 2.5
3. Calculate the sum for the second group (Probability = 1/12)
Sum2 = 3(1/12) + 4(1/12) + 6(1/12) + 8(1/12)
Sum2 = (3 + 4 + 6 + 8) / 12
Sum2 = 21 / 12 = 7 / 4 = 1.75
4. Calculate the Total Expected Value E[X]
E[X] = Sum1 + Sum2
E[X] = 2.5 + 1.75 = 4.25
Correct Answer: 4.25

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