Which of the following operations to compute π result(s) in an arithmetic overflow?
Correct : a,c
The correct answers are Option A (Z = X β Y) and Option C (Z = βX + Y).
First, let''s decode the two signed magnitude numbers. In signed magnitude, the MSB is the sign bit (1=negative, 0=positive) and the remaining 7 bits give the magnitude.
X = 10110100: Sign = 1 (negative), magnitude = 01101002 = 52. So X = β52.
Y = 01001100: Sign = 0 (positive), magnitude = 10011002 = 76. So Y = +76.
For 8-bit signed magnitude, the valid range is β127 to +127 (7 bits for magnitude, max = 127). Any result with magnitude > 127 causes overflow.
Now evaluate each operation:
Option A β Z = X β Y = β52 β 76 = β128: Magnitude = 128 > 127 β Overflow β
Option B β Z = X + Y = β52 + 76 = +24: Magnitude = 24 β€ 127 β No overflow
Option C β Z = βX + Y = +52 + 76 = +128: Magnitude = 128 > 127 β Overflow β
Option D β Z = βX β Y = +52 β 76 = β24: Magnitude = 24 β€ 127 β No overflow
Both A and C produce a result of magnitude 128, which exceeds the 7-bit magnitude limit of 127, causing overflow in signed magnitude representation.
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