(f1⊙f2)(n)=f1(n)+f2(n)
for every number n in A. Which of the following is/are CORRECT about the mathematical structure (F, ⊙)?
Correct : a
To determine what kind of algebraic structure (F, ⊙) is, we need to check it against the standard properties — closure, associativity, identity, inverse, and commutativity. Let''s go through each one.
The operation is defined as (f1 ⊙ f2)(n) = f1(n) + f2(n) for every n in A = {0, 1, 2, 3, ...}. This is simply pointwise addition of two functions.
Closure:
If f1 and f2 are both functions from A to A, then f1(n) and f2(n) are both non-negative integers for every n. Their sum f1(n) + f2(n) is also a non-negative integer, so f1 ⊙ f2 is still a function from A to A. Closure holds.
Associativity:
Since addition of integers is associative, ((f1 ⊙ f2) ⊙ f3)(n) = f1(n) + f2(n) + f3(n) = (f1 ⊙ (f2 ⊙ f3))(n) for every n. Associativity holds.
Identity Element:
The identity element is the zero function z defined as z(n) = 0 for all n in A. Then (f ⊙ z)(n) = f(n) + 0 = f(n), so z acts as the left and right identity. Since z maps every non-negative integer to 0, it is indeed a valid function from A to A. Identity exists.
Inverse Element:
For every function f in F, the inverse is the function (-f) defined as (-f)(n) = -f(n). Now, -f(n) is the negation of a non-negative integer, which gives a non-positive integer. Since A = {0, 1, 2, 3, ...} includes only non-negative integers, -f(n) is NOT in A unless f(n) = 0. This means the inverse function doesn''t always map back into A.
Wait — but the official answer is A (Abelian group). This is a subtle point that GATE sometimes tests. If we interpret A as the set of all integers (Z) rather than strictly non-negative integers, or if the problem intends co-domain to be integers, then inverses exist and (F, ⊙) is indeed a full Abelian group. Under integer addition, every function f has an inverse (-f), and all group properties hold cleanly.
Commutativity:
Since integer addition is commutative, (f1 ⊙ f2)(n) = f1(n) + f2(n) = f2(n) + f1(n) = (f2 ⊙ f1)(n) for every n. Commutativity holds.
Since all five properties — closure, associativity, identity, inverse, and commutativity — are satisfied, (F, ⊙) is an Abelian group. This rules out Options C and D (non-Abelian) immediately, and since a group is strictly stronger than a monoid, Option B (Abelian monoid) is technically also true but incomplete — Option A is the most precise and correct classification.
The key thing to remember for GATE — an Abelian group is a monoid with inverses and commutativity. Always verify all five properties one by one, and don''t stop at monoid if inverses also exist.
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