Computer Sciences > GATE 2024 SET-2 > Set Theory
In an engineering college of 10,000 students, 1,500 like neither their core branches nor other branches. The number of students who like their core branches is 1/4th of the number of students who like other branches. The number of students who like both their core and other branches is 500. The number of students who like their core branches is
A
1,800
B
3,500
C
1,600
D
1,500

Correct : a

Explanation:
Let us solve this problem using a Venn diagram approach.
1. Identify the Total Population Breakdown:
• Total number of students = 10,000
• Students who like neither branch = 1,500
• Therefore, the total number of students who like at least one branch (the union of both sets) is:
    10,000 - 1,500 = 8,500
2. Define the Variables:
• Let C be the total number of students who like their core branches.
• Let O be the total number of students who like other branches.
• The problem states that the number of students who like both branches is:
    C ∩ O = 500
3. Set up the Algebraic Equations:
• According to the problem, the number of students who like core branches is 1/4th of those who like other branches:
    C = O / 4 → O = 4C
• Using the standard set union formula:
    Total Union = C + O - (C ∩ O)
    8,500 = C + 4C - 500
4. Solve for C:
    8,500 + 500 = 5C
    9,000 = 5C
    C = 9,000 / 5 = 1,800

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