Computer Sciences > Gate 2022 > Round Robin Algorithm
Consider four processes P, Q, R, and S scheduled on a CPU as per round robin algorithm with a time quantum of 4 units. The processes arrive in the order P, Q, R, S, all at time t = 0. There is exactly one context switch from S to Q, exactly one context switch from R to Q, and exactly two context switches from Q to R. There is no context switch from S to P. Switching to a ready process after the termination of another process is also considered a context switch. Which one of the following is NOT possible as CPU burst time (in time units) of these processes?
A
P=4, Q=10, R=6, S=2
B
P=2, Q=9, R=5, S=1
C
P=4, Q=12, R=5, S=4
D
P=3, Q=7, R=7, S=3

Correct : d

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