Unit weight γ = 15.72 kN/m3
Cohesion c′ = 12 kPa
Angle of internal friction φ′ = 15°
The critical height of the slope (in m) is ______ (rounded off to two decimal places).
Correct : 5.21
The critical height of a slope is the maximum height at which the slope remains stable (Factor of Safety = 1). For a cohesive frictional soil, this is determined using Taylor''s stability chart.
The stability number Ns is obtained from Taylor''s chart for slope angle β = 22° and angle of friction φ′ = 15°. For these values, Ns ≈ 6.83.
The critical height is then:
Hc = Ns × c′/γ
Hc = 6.83 × 12/15.72
Hc = 81.96/15.72
Hc = 5.21 m
Taylor''s stability chart is the standard method for determining critical heights of slopes in cohesive frictional soils, where both cohesion and friction contribute to stability. The critical height decreases as the slope angle increases or as soil strength decreases.
Correct answer: 5.21 m ✓
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