Chemical Engineering > GATE 2018 > Rheology
At a shear rate of 10 s−1, the apparent viscosity of a non-Newtonian liquid was found to be 1 Pa·s.
At a shear rate of 100 s−1, the apparent viscosity of the same liquid was found to be 0.5 Pa·s.
If the liquid follows power law behavior, the apparent viscosity (in Pa·s) at a shear stress of 10 N m−2 is _____________ (rounded off to two decimal place).
At a shear rate of 100 s−1, the apparent viscosity of the same liquid was found to be 0.5 Pa·s.
If the liquid follows power law behavior, the apparent viscosity (in Pa·s) at a shear stress of 10 N m−2 is _____________ (rounded off to two decimal place).
Correct : 1.00
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