Chemical Engineering > GATE 2018 > Fluid Dynamics
The initial water level in a tank is 4 m. When the valve located at the bottom is opened, the rate of change of water level (L) with respect to time (t) is,
dL/dt = −k√t, where
k = 0.6 m s−3/2.
The level of water (in m) in the tank at time 0.5 s after opening the valve is ____________ (rounded off to second decimal place).
dL/dt = −k√t, where
k = 0.6 m s−3/2.
The level of water (in m) in the tank at time 0.5 s after opening the valve is ____________ (rounded off to second decimal place).
Correct : 3.80
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