Biomedical Engineering > GATE 2021 > Cardiac Output Measurement
An inexperienced clinician was measuring the cardiac output of a healthy human by thermodilution technique. A 2.0 mL of cold saline solution of volume (Vi) at 7 °C was injected at the entrance of the right atrium. The change in blood temperature (∫0t1ΔTbdt) at the pulmonary artery was measured to be -20 Kelvin. second. The cardiac output F was calculated using the following formula
F = Q/(ρbcb0t1ΔTbdt)
where Q is the heat content of injectate in Joules, given by ViΔTiρici and ΔTi is the temperature difference between the injectate and blood. It was assumed that the density of blood (ρb in kg/m³) and the specific heat capacity of blood (cb in J/(kg.K)) were respectively equal to that of the injectate ρi and ci.
The clinician realized that there was an error in the measurement of F. Which of the following is TRUE?
A
Cardiac output is too low because the cold saline volume was too small
B
Cardiac output is too low because ∫0t1ΔTbdt is too large
C
Cardiac output is too high because the cold saline volume was too large
D
Cardiac output is too high because ∫0t1ΔTbdt is too small

Correct : a, b

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