Aerospace Engineering > GATE 2019 > Escape Velocity
The product of earth's mass (M) and the universal gravitational constant (G) is GM = 3.986 x 10^14 m^3/s^2. The radius of earth is 6371 km. The minimum increment in the velocity to be imparted to a spacecraft flying in a circular orbit around the earth at an altitude of 4000 km to make it exit earth's gravitational field is _______ km/s (round off to 2 decimal places).
Correct : 2.54 to 2.62
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